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Дана таблица orders с колонками order_id, customer_id, order_date, total_amount. Какой из следующих SQL запросов вернет топ-3 месяца с наибольшим количеством заказов?

A) SELECT MONTH(order_date) AS month, SUM(total_amount) AS total_order_amount
FROM orders
GROUP BY month
ORDER BY total_order_amount DESC
LIMIT 3;

B) SELECT EXTRACT(MONTH FROM order_date) AS month, SUM(total_amount) AS total_order_amount
FROM orders
GROUP BY month
ORDER BY total_order_amount DESC
LIMIT 3;

C) SELECT DATE_TRUNC('month', order_date) AS month, SUM(total_amount) AS total_order_amount
FROM orders
GROUP BY month
ORDER BY total_order_amount DESC
LIMIT 3;

D) SELECT STRFTIME('%Y-%m', order_date) AS month, SUM(total_amount) AS total_order_amount
FROM orders
GROUP BY month
ORDER BY total_order_amount DESC
LIMIT 3;

Ответить на вопрос можно ниже ⬇️



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Дана таблица orders с колонками order_id, customer_id, order_date, total_amount. Какой из следующих SQL запросов вернет топ-3 месяца с наибольшим количеством заказов?

A) SELECT MONTH(order_date) AS month, SUM(total_amount) AS total_order_amount
FROM orders
GROUP BY month
ORDER BY total_order_amount DESC
LIMIT 3;

B) SELECT EXTRACT(MONTH FROM order_date) AS month, SUM(total_amount) AS total_order_amount
FROM orders
GROUP BY month
ORDER BY total_order_amount DESC
LIMIT 3;

C) SELECT DATE_TRUNC('month', order_date) AS month, SUM(total_amount) AS total_order_amount
FROM orders
GROUP BY month
ORDER BY total_order_amount DESC
LIMIT 3;

D) SELECT STRFTIME('%Y-%m', order_date) AS month, SUM(total_amount) AS total_order_amount
FROM orders
GROUP BY month
ORDER BY total_order_amount DESC
LIMIT 3;

Ответить на вопрос можно ниже ⬇️

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