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Answer to Q135

Three types of drinks each worth $6.00/ltr, $7.50/ltr and $x/ltr are mixed in proportion of 1 : 2 : 3 to form a cocktail worth $8.50/ltr. What is the value of x in $/ltr?

Three types of drinks each worth $6.00/ltr, $7.50/ltr and $x/ltr
A = $6.00/ltr
B = $7.50/ltr
C = $x/ltr

are mixed in proportion of 1 : 2 : 3 to form a cocktail worth $8.50/ltr
1+2+3 = 6

so,
[(1÷6)*A] + [(2÷6)*B] + [(3÷6)*C] = $8.50/ltr
[(1÷6)*6] + [(2÷6)*7.5] + [(3÷6)*C] = 8.50
1 + 2.5 + 0.5C = 8.50
3.5 + 0.5C = 8.50
0.5C = 8.50 - 3.50
0.5C = 5
C = 5 ÷ 0.5
C = 10

Answer: 10.00



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Answer to Q135

Three types of drinks each worth $6.00/ltr, $7.50/ltr and $x/ltr are mixed in proportion of 1 : 2 : 3 to form a cocktail worth $8.50/ltr. What is the value of x in $/ltr?

Three types of drinks each worth $6.00/ltr, $7.50/ltr and $x/ltr
A = $6.00/ltr
B = $7.50/ltr
C = $x/ltr

are mixed in proportion of 1 : 2 : 3 to form a cocktail worth $8.50/ltr
1+2+3 = 6

so,
[(1÷6)*A] + [(2÷6)*B] + [(3÷6)*C] = $8.50/ltr
[(1÷6)*6] + [(2÷6)*7.5] + [(3÷6)*C] = 8.50
1 + 2.5 + 0.5C = 8.50
3.5 + 0.5C = 8.50
0.5C = 8.50 - 3.50
0.5C = 5
C = 5 ÷ 0.5
C = 10

Answer: 10.00

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