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Что выведет этот код на Java?


public class Main {
public static void main(String[] args) {
String a = "hello";
String b = "he" + "llo";
String c = "he";
String d = c + "llo";

System.out.println(a == b); // #1
System.out.println(a == d); // #2
System.out.println(a.equals(d)); // #3
}
}


🔢 Варианты ответа:

A)

true
true


B)

false
true


C)

false
true


D)

false
false


Правильный ответ: B

💡 Почему?
- Строки в Java — immutable и используют string pool.
-
a == btrue, потому что "he" + "llo" конкатенируется на этапе компиляции.
-
c + "llo" — создаёт новый объект во время выполнения.
-
a == dfalse, но a.equals(d)true, потому что .equals() сравнивает содержимое строк.

@javatg



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Что выведет этот код на Java?


public class Main {
public static void main(String[] args) {
String a = "hello";
String b = "he" + "llo";
String c = "he";
String d = c + "llo";

System.out.println(a == b); // #1
System.out.println(a == d); // #2
System.out.println(a.equals(d)); // #3
}
}


🔢 Варианты ответа:

A)

true
true


B)

false
true


C)

false
true


D)

false
false


Правильный ответ: B

💡 Почему?
- Строки в Java — immutable и используют string pool.
-
a == btrue, потому что "he" + "llo" конкатенируется на этапе компиляции.
-
c + "llo" — создаёт новый объект во время выполнения.
-
a == dfalse, но a.equals(d)true, потому что .equals() сравнивает содержимое строк.

@javatg

BY Java


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