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What is the output of the program?

A. 4
B. 5
C. 6
D. 7
E. 13
F. The code will not compile because of line 7

Explanation:
The code compiles and runs without issue; therefore, option F is incorrect. Let's examine one loop iteration at a time.
📍 The loop continues as count loop expression evaluates to 0 < 3, which is true, with y taking a new value of 1. The value of y is set to:
y = (1 + 2 * 1) % 3 = (1 + 2) % 3 = 3 % 3 = 0
📍 The first case block is called and the value of x is then set to: x = 3 - 1 = 2
📍 The loop continues as count loop expression evaluates to 1 < 3, which is true, with y taking a new value of 2. The value of y is set to:
y = (1 + 2 * 2) % 3 = (1 + 4) % 3 = 4 % 3 = 2
📍 The default block is called and the value of x is set to: x = 2 - 1 = 1
📍 The loop continues as the count loop expression evaluates to 2 < 3, which is true, with y taking a new value of 3. The value of y is set to:
y = (1 + 2 * 3) % 3 = (1 + 6) % 3 = 7 % 3 = 1
📍 The second case block is called and the value of x is then set to: x = 1 + 5 = 6
📍 The loop ends as the count loop expression evaluates to 3 < 3, with y also taking a new value of 4. The most recent value of x, 6, is output, so the answer is option C.



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What is the output of the program?

A. 4
B. 5
C. 6
D. 7
E. 13
F. The code will not compile because of line 7

Explanation:
The code compiles and runs without issue; therefore, option F is incorrect. Let's examine one loop iteration at a time.
📍 The loop continues as count loop expression evaluates to 0 < 3, which is true, with y taking a new value of 1. The value of y is set to:
y = (1 + 2 * 1) % 3 = (1 + 2) % 3 = 3 % 3 = 0
📍 The first case block is called and the value of x is then set to: x = 3 - 1 = 2
📍 The loop continues as count loop expression evaluates to 1 < 3, which is true, with y taking a new value of 2. The value of y is set to:
y = (1 + 2 * 2) % 3 = (1 + 4) % 3 = 4 % 3 = 2
📍 The default block is called and the value of x is set to: x = 2 - 1 = 1
📍 The loop continues as the count loop expression evaluates to 2 < 3, which is true, with y taking a new value of 3. The value of y is set to:
y = (1 + 2 * 3) % 3 = (1 + 6) % 3 = 7 % 3 = 1
📍 The second case block is called and the value of x is then set to: x = 1 + 5 = 6
📍 The loop ends as the count loop expression evaluates to 3 < 3, with y also taking a new value of 4. The most recent value of x, 6, is output, so the answer is option C.

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