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🦀 Задача на Rust: "Найди пропавшее число"

Условие
У тебя есть Vec<String>, в котором находятся строки от "1" до "100", но одно число отсутствует.
Найди его без использования sort, HashMap, iter().sum() и т. д.
Можно использовать parse::<u32>().

Формат функции:


fn find_missing_number(data: &Vec<String>) -> u32


Решение через XOR:


fn find_missing_number(data: &Vec<String>) -> u32 {
let mut xor_full = 0;
let mut xor_data = 0;

for i in 1..=100 {
xor_full ^= i;
}

for s in data {
if let Ok(n) = s.parse::<u32>() {
xor_data ^= n;
}
}

xor_full ^ xor_data
}


Пример использования:


fn main() {
let mut data: Vec<String> = (1..=100)
.filter(|&x| x != 42)
.map(|x| x.to_string())
.collect();

use rand::seq::SliceRandom;
let mut rng = rand::thread_rng();
data.shuffle(&mut rng);

let missing = find_missing_number(&data);
println!("Пропущено: {}", missing); // Ожидается 42
}


Зависимости в `Cargo.toml`:


[dependencies]
rand = "0.8"


Объяснение:
XOR всех чисел от 1 до 100 ⊕ XOR из входных данных → пропущенное число.
Работает, потому что a ^ a = 0, 0 ^ b = b.



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🦀 Задача на Rust: "Найди пропавшее число"

Условие
У тебя есть Vec<String>, в котором находятся строки от "1" до "100", но одно число отсутствует.
Найди его без использования sort, HashMap, iter().sum() и т. д.
Можно использовать parse::<u32>().

Формат функции:


fn find_missing_number(data: &Vec<String>) -> u32


Решение через XOR:


fn find_missing_number(data: &Vec<String>) -> u32 {
let mut xor_full = 0;
let mut xor_data = 0;

for i in 1..=100 {
xor_full ^= i;
}

for s in data {
if let Ok(n) = s.parse::<u32>() {
xor_data ^= n;
}
}

xor_full ^ xor_data
}


Пример использования:


fn main() {
let mut data: Vec<String> = (1..=100)
.filter(|&x| x != 42)
.map(|x| x.to_string())
.collect();

use rand::seq::SliceRandom;
let mut rng = rand::thread_rng();
data.shuffle(&mut rng);

let missing = find_missing_number(&data);
println!("Пропущено: {}", missing); // Ожидается 42
}


Зависимости в `Cargo.toml`:


[dependencies]
rand = "0.8"


Объяснение:
XOR всех чисел от 1 до 100 ⊕ XOR из входных данных → пропущенное число.
Работает, потому что a ^ a = 0, 0 ^ b = b.

BY Rust


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