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What is the output of the program?

A. 4
B. 5
C. 6
D. 7
E. 13
F. The code will not compile because of line 7

Explanation:
The code compiles and runs without issue; therefore, option F is incorrect. Let's examine one loop iteration at a time.
📍 The loop continues as count loop expression evaluates to 0 < 3, which is true, with y taking a new value of 1. The value of y is set to:
y = (1 + 2 * 1) % 3 = (1 + 2) % 3 = 3 % 3 = 0
📍 The first case block is called and the value of x is then set to: x = 3 - 1 = 2
📍 The loop continues as count loop expression evaluates to 1 < 3, which is true, with y taking a new value of 2. The value of y is set to:
y = (1 + 2 * 2) % 3 = (1 + 4) % 3 = 4 % 3 = 2
📍 The default block is called and the value of x is set to: x = 2 - 1 = 1
📍 The loop continues as the count loop expression evaluates to 2 < 3, which is true, with y taking a new value of 3. The value of y is set to:
y = (1 + 2 * 3) % 3 = (1 + 6) % 3 = 7 % 3 = 1
📍 The second case block is called and the value of x is then set to: x = 1 + 5 = 6
📍 The loop ends as the count loop expression evaluates to 3 < 3, with y also taking a new value of 4. The most recent value of x, 6, is output, so the answer is option C.



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What is the output of the program?

A. 4
B. 5
C. 6
D. 7
E. 13
F. The code will not compile because of line 7

Explanation:
The code compiles and runs without issue; therefore, option F is incorrect. Let's examine one loop iteration at a time.
📍 The loop continues as count loop expression evaluates to 0 < 3, which is true, with y taking a new value of 1. The value of y is set to:
y = (1 + 2 * 1) % 3 = (1 + 2) % 3 = 3 % 3 = 0
📍 The first case block is called and the value of x is then set to: x = 3 - 1 = 2
📍 The loop continues as count loop expression evaluates to 1 < 3, which is true, with y taking a new value of 2. The value of y is set to:
y = (1 + 2 * 2) % 3 = (1 + 4) % 3 = 4 % 3 = 2
📍 The default block is called and the value of x is set to: x = 2 - 1 = 1
📍 The loop continues as the count loop expression evaluates to 2 < 3, which is true, with y taking a new value of 3. The value of y is set to:
y = (1 + 2 * 3) % 3 = (1 + 6) % 3 = 7 % 3 = 1
📍 The second case block is called and the value of x is then set to: x = 1 + 5 = 6
📍 The loop ends as the count loop expression evaluates to 3 < 3, with y also taking a new value of 4. The most recent value of x, 6, is output, so the answer is option C.

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Telegram has no known backdoors and, even though it is come in for criticism for using proprietary encryption methods instead of open-source ones, those have yet to be compromised. While no messaging app can guarantee a 100% impermeable defense against determined attackers, Telegram is vulnerabilities are few and either theoretical or based on spoof files fooling users into actively enabling an attack.

A project of our size needs at least a few hundred million dollars per year to keep going,” Mr. Durov wrote in his public channel on Telegram late last year. “While doing that, we will remain independent and stay true to our values, redefining how a tech company should operate.

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