1: public class Fish { 2: public static void main(String[] args) { 3: int numFish = 4; 4: String fishType = "tuna"; 5: String anotherFish = numFish + 1; 6: System.out.println(anotherFish + " " + fishType); 7: System.out.println(numFish + " " + 1); 8: } }
❌ A. 4 1 ❌ B. 41 ❌ C. 5 ❌ D. 5 tuna ❌ E. 5tuna ❌ F. 51tuna ✅ G. The code does not compile
Explanation: Line 5 does not compile. This question is checking to see if you are paying attention to the types. numFish is an int and 1 is an int. Therefore, we use numeric addition and get 5. The problem is that we can’t store an int in a String variable. Supposing line 5 said String anotherFish = numFish + 1 + "";. In that case, the answer would be options A and D. The variable defined on line 5 would be the string "5", and both output statements would use concatenation.
1: public class Fish { 2: public static void main(String[] args) { 3: int numFish = 4; 4: String fishType = "tuna"; 5: String anotherFish = numFish + 1; 6: System.out.println(anotherFish + " " + fishType); 7: System.out.println(numFish + " " + 1); 8: } }
❌ A. 4 1 ❌ B. 41 ❌ C. 5 ❌ D. 5 tuna ❌ E. 5tuna ❌ F. 51tuna ✅ G. The code does not compile
Explanation: Line 5 does not compile. This question is checking to see if you are paying attention to the types. numFish is an int and 1 is an int. Therefore, we use numeric addition and get 5. The problem is that we can’t store an int in a String variable. Supposing line 5 said String anotherFish = numFish + 1 + "";. In that case, the answer would be options A and D. The variable defined on line 5 would be the string "5", and both output statements would use concatenation.
BY Explanations “Top Java Quiz Questions”
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