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What is the result of the following program?
1: public class Squares {
2: public static long square(int x) {
3: long y = x * (long) x;
4: x = -1;
5: return y;
6: }
7: public static void main(String[] args) {
8: int value = 9;
9: long result = square(value);
10: System.out.println(value);
11: } }


A. -1
B. 9
C. 81
D. Compiler error on line 9.
E. Compiler error on a different line

Explanation:
Since Java is pass-by-value and the variable on line 8 never gets reassigned, it stays as 9. In the method square, x starts as 9. y becomes 81 and then x gets set to –1. Line 9 does set result to 81. However, we are printing out value and that is still 9.



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What is the result of the following program?

1: public class Squares {
2: public static long square(int x) {
3: long y = x * (long) x;
4: x = -1;
5: return y;
6: }
7: public static void main(String[] args) {
8: int value = 9;
9: long result = square(value);
10: System.out.println(value);
11: } }


A. -1
B. 9
C. 81
D. Compiler error on line 9.
E. Compiler error on a different line

Explanation:
Since Java is pass-by-value and the variable on line 8 never gets reassigned, it stays as 9. In the method square, x starts as 9. y becomes 81 and then x gets set to –1. Line 9 does set result to 81. However, we are printing out value and that is still 9.

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